33y^2=2525

Solution for 33y^2=2525 equation:

33y^2=2525

We move all terms to the left:

33y^2-(2525)=0

a = 33; b = 0; c = -2525;
Δ = b2-4ac
Δ = 02-4·33·(-2525)
Δ = 333300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{333300}=\sqrt{100*3333}=\sqrt{100}*\sqrt{3333}=10\sqrt{3333}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{3333}}{2*33}=\frac{0-10\sqrt{3333}}{66}
=-\frac{10\sqrt{3333}}{66}
=-\frac{5\sqrt{3333}}{33}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{3333}}{2*33}=\frac{0+10\sqrt{3333}}{66}
=\frac{10\sqrt{3333}}{66}
=\frac{5\sqrt{3333}}{33}
$